फलन (f(x)=3-\sqrt{x-1}) का अधिकतम मान क्या है?

What is the maximum value of (f(x)=3-\sqrt{x-1})?

Explanation opens after your attempt
Correct Answer

A. (3)

Step 1

Concept

Since \(\sqrt{x-1}\ge 0\), \(3-\sqrt{x-1}\le 3\). The maximum value (3) occurs at (x=1).

Step 2

Why this answer is correct

The correct answer is A. (3). Since \(\sqrt{x-1}\ge 0\), \(3-\sqrt{x-1}\le 3\). The maximum value (3) occurs at (x=1).

Step 3

Exam Tip

\(\sqrt{x-1}\ge 0\), इसलिए \(3-\sqrt{x-1}\le 3\)। अधिकतम मान (3) (x=1) पर मिलता है।

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Mathematics Answer, Explanation and Revision Hints

फलन (f(x)=3-\sqrt{x-1}) का अधिकतम मान क्या है? / What is the maximum value of (f(x)=3-\sqrt{x-1})?

Correct Answer: A. (3). Explanation: \(\sqrt{x-1}\ge 0\), इसलिए \(3-\sqrt{x-1}\le 3\)। अधिकतम मान (3) (x=1) पर मिलता है। / Since \(\sqrt{x-1}\ge 0\), \(3-\sqrt{x-1}\le 3\). The maximum value (3) occurs at (x=1).

Which concept should I revise for this Mathematics MCQ?

Since \(\sqrt{x-1}\ge 0\), \(3-\sqrt{x-1}\le 3\). The maximum value (3) occurs at (x=1).

What exam hint can help solve this Mathematics question?

\(\sqrt{x-1}\ge 0\), इसलिए \(3-\sqrt{x-1}\le 3\)। अधिकतम मान (3) (x=1) पर मिलता है।