असमानता \(\frac{2x+7}{3}\le\frac{x+11}{2}\) का संख्या रेखा पर सही हल क्या है?
What is the correct number line solution of \(\frac{2x+7}{3}\le\frac{x+11}{2}\)?
Explanation opens after your attempt
A. \(x\le19\), (19) पर बंद बिंदु और बाईं ओर\(x\le19\), closed dot at (19) shaded left
Concept
Multiplying by (6) gives \(4x+14\le3x+33\), so \(x\le19\). In exams, multiply by the LCM to clear fractions.
Why this answer is correct
The correct answer is A. \(x\le19\), (19) पर बंद बिंदु और बाईं ओर / \(x\le19\), closed dot at (19) shaded left. Multiplying by (6) gives \(4x+14\le3x+33\), so \(x\le19\). In exams, multiply by the LCM to clear fractions.
Exam Tip
(6) से गुणा करने पर \(4x+14\le3x+33\), इसलिए \(x\le19\)। परीक्षा में भिन्न हटाने के लिए LCM से गुणा करें।
Login to save your score, XP, coins and progress.
