\(^{n}C_1+^{n}C_3+^{n}C_5+\cdots\) का योग किसके बराबर होता है?
The sum \(^{n}C_1+^{n}C_3+^{n}C_5+\cdots\) is equal to what?
Explanation opens after your attempt
Correct Answer
C. \(2^{n-1}\)
Concept
The sum of odd indexed combinations equals the even indexed sum, \(2^{n-1}\). In exams remember the alternating identity from ((1-1)^n).
Why this answer is correct
The correct answer is C. \(2^{n-1}\). The sum of odd indexed combinations equals the even indexed sum, \(2^{n-1}\). In exams remember the alternating identity from ((1-1)^n).
Exam Tip
Odd indexed combinations का योग even indexed sum के बराबर \(2^{n-1}\) होता है। परीक्षा में ((1-1)^n) से alternating identity याद रखें।
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