असमानता \(-1\le 2x+3\le 11\) और (x>0) को साथ लेने पर संख्या रेखा पर कौन-सा interval मिलेगा?

Taking \(-1\le 2x+3\le 11\) and (x>0) together, which interval is obtained on the number line?

Explanation opens after your attempt
Correct Answer

B. ((0,4])

Step 1

Concept

The first inequality gives \(-2\le x\le4\), and the second gives (x>0), so the common part is ((0,4]). In exams, apply the extra condition as an intersection.

Step 2

Why this answer is correct

The correct answer is B. ((0,4]). The first inequality gives \(-2\le x\le4\), and the second gives (x>0), so the common part is ((0,4]). In exams, apply the extra condition as an intersection.

Step 3

Exam Tip

पहली असमानता से \(-2\le x\le4\) और दूसरी से (x>0), इसलिए common भाग ((0,4]) है। परीक्षा में extra condition लगाकर intersection लें।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

असमानता \(-1\le 2x+3\le 11\) और (x>0) को साथ लेने पर संख्या रेखा पर कौन-सा interval मिलेगा? / Taking \(-1\le 2x+3\le 11\) and (x>0) together, which interval is obtained on the number line?

Correct Answer: B. ((0,4]). Explanation: पहली असमानता से \(-2\le x\le4\) और दूसरी से (x>0), इसलिए common भाग ((0,4]) है। परीक्षा में extra condition लगाकर intersection लें। / The first inequality gives \(-2\le x\le4\), and the second gives (x>0), so the common part is ((0,4]). In exams, apply the extra condition as an intersection.

Which concept should I revise for this Mathematics MCQ?

The first inequality gives \(-2\le x\le4\), and the second gives (x>0), so the common part is ((0,4]). In exams, apply the extra condition as an intersection.

What exam hint can help solve this Mathematics question?

पहली असमानता से \(-2\le x\le4\) और दूसरी से (x>0), इसलिए common भाग ((0,4]) है। परीक्षा में extra condition लगाकर intersection लें।