ग्राफ \(y=|x^2-1|\) किस अंतराल में \(y=1-x^2\) के बराबर है?

On which interval is the graph \(y=|x^2-1|\) equal to \(y=1-x^2\)?

Explanation opens after your attempt
Correct Answer

A. \(-1\le x\le1\)

Step 1

Concept

When \(x^2-1\le0\), \(|x^2-1|=1-x^2\), so \(-1\le x\le1\). First determine the sign inside the modulus.

Step 2

Why this answer is correct

The correct answer is A. \(-1\le x\le1\). When \(x^2-1\le0\), \(|x^2-1|=1-x^2\), so \(-1\le x\le1\). First determine the sign inside the modulus.

Step 3

Exam Tip

जब \(x^2-1\le0\), तब \(|x^2-1|=1-x^2\), इसलिए \(-1\le x\le1\)। मापांक में अंदर का चिन्ह पहले तय करें।

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Mathematics Answer, Explanation and Revision Hints

ग्राफ \(y=|x^2-1|\) किस अंतराल में \(y=1-x^2\) के बराबर है? / On which interval is the graph \(y=|x^2-1|\) equal to \(y=1-x^2\)?

Correct Answer: A. \(-1\le x\le1\). Explanation: जब \(x^2-1\le0\), तब \(|x^2-1|=1-x^2\), इसलिए \(-1\le x\le1\)। मापांक में अंदर का चिन्ह पहले तय करें। / When \(x^2-1\le0\), \(|x^2-1|=1-x^2\), so \(-1\le x\le1\). First determine the sign inside the modulus.

Which concept should I revise for this Mathematics MCQ?

When \(x^2-1\le0\), \(|x^2-1|=1-x^2\), so \(-1\le x\le1\). First determine the sign inside the modulus.

What exam hint can help solve this Mathematics question?

जब \(x^2-1\le0\), तब \(|x^2-1|=1-x^2\), इसलिए \(-1\le x\le1\)। मापांक में अंदर का चिन्ह पहले तय करें।