त्रिज्या (63) मीटर वाले वृत्ताकार पथ पर \(40^\circ\) केंद्रीय कोण के बराबर चली दूरी क्या है?
On a circular track of radius (63) m what is the distance covered for a central angle of \(40^\circ\)?
Explanation opens after your attempt
Correct Answer
B. \(14\pi\) मीटर\(14\pi\) m
Concept
\(40^\circ=\frac{2\pi}{9}\) radians. The distance is \(s=63\times\frac{2\pi}{9}=14\pi\) m.
Why this answer is correct
The correct answer is B. \(14\pi\) मीटर / \(14\pi\) m. \(40^\circ=\frac{2\pi}{9}\) radians. The distance is \(s=63\times\frac{2\pi}{9}=14\pi\) m.
Exam Tip
\(40^\circ=\frac{2\pi}{9}\) रेडियन है। दूरी \(s=63\times\frac{2\pi}{9}=14\pi\) मीटर होगी।
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