यदि (x) एक वास्तविक संख्या है, तो \(x^2+1>0\) का हल क्या है?
If (x) is a real number, what is the solution of \(x^2+1>0\)?
Explanation opens after your attempt
Correct Answer
C. सभी \(x\in \mathbb{R}\)All \(x\in \mathbb{R}\)
Concept
Since \(x^2\geq 0\), \(x^2+1\geq 1>0\) for all real (x). Recognizing always positive forms is useful.
Why this answer is correct
The correct answer is C. सभी \(x\in \mathbb{R}\) / All \(x\in \mathbb{R}\). Since \(x^2\geq 0\), \(x^2+1\geq 1>0\) for all real (x). Recognizing always positive forms is useful.
Exam Tip
क्योंकि \(x^2\geq 0\), इसलिए \(x^2+1\geq 1>0\) सभी वास्तविक (x) के लिए सत्य है। धनात्मक निश्चित रूप पहचानना उपयोगी है।
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