यदि \(x\in\mathbb{Z}\) और \(-\frac{11}{3}\le x<\frac{9}{2}\), तो संख्या रेखा पर कौन-से पूर्णांक बिंदु मिलेंगे?
If \(x\in\mathbb{Z}\) and \(-\frac{11}{3}\le x<\frac{9}{2}\), which integer points will appear on the number line?
Explanation opens after your attempt
B. ({-3,-2,-1,0,1,2,3,4})
Concept
The first integer greater than or equal to \(-\frac{11}{3}\) is (-3), and the last integer less than \(\frac{9}{2}\) is (4). In exams, choose valid integers separately at fractional boundaries.
Why this answer is correct
The correct answer is B. ({-3,-2,-1,0,1,2,3,4}). The first integer greater than or equal to \(-\frac{11}{3}\) is (-3), and the last integer less than \(\frac{9}{2}\) is (4). In exams, choose valid integers separately at fractional boundaries.
Exam Tip
\(-\frac{11}{3}\) से बड़ा या बराबर पहला पूर्णांक (-3) है और \(\frac{9}{2}\) से छोटा अंतिम पूर्णांक (4) है। परीक्षा में fractional boundary पर valid integer अलग से चुनें।
Login to save your score, XP, coins and progress.
