यदि \(x \ge 0\), \(y \ge 0\), \(x+2y \le 14\) और \(3x+y \le 18\) हों तो दोनों तिरछी सीमा रेखाओं का प्रतिच्छेद बिंदु कौन सा है?
If \(x \ge 0\), \(y \ge 0\), \(x+2y \le 14\), and \(3x+y \le 18\), what is the intersection point of the two slant boundary lines?
Explanation opens after your attempt
Correct Answer
A. (\left\(\frac{22}{5},\frac{24}{5}\right\))
Concept
Solving (x+2y=14) and (3x+y=18) gives \(x=\frac{22}{5}\), \(y=\frac{24}{5}\). In a graph, always find the intersection of slant boundaries separately.
Why this answer is correct
The correct answer is A. (\left\(\frac{22}{5},\frac{24}{5}\right\)). Solving (x+2y=14) and (3x+y=18) gives \(x=\frac{22}{5}\), \(y=\frac{24}{5}\). In a graph, always find the intersection of slant boundaries separately.
Exam Tip
(x+2y=14) और (3x+y=18) हल करने पर \(x=\frac{22}{5}\), \(y=\frac{24}{5}\) मिलता है। ग्राफ में तिरछी सीमाओं का प्रतिच्छेद अलग से जरूर निकालें।
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