यदि \(U={x:x\in\mathbb{Z},-6\le x\le 6}\) और \(A={x:x^2=16}\) है, तो (n\(A^c\)) कितना होगा?

If \(U={x:x\in\mathbb{Z},-6\le x\le 6}\) and \(A={x:x^2=16}\), what is (n\(A^c\))?

Explanation opens after your attempt
Correct Answer

A. (11)

Step 1

Concept

There are (13) integers in (U), and \(A=\{-4,4\}\). Hence (n\(A^c\)=13-2=11).

Step 2

Why this answer is correct

The correct answer is A. (11). There are (13) integers in (U), and \(A=\{-4,4\}\). Hence (n\(A^c\)=13-2=11).

Step 3

Exam Tip

(U) में (13) पूर्णांक हैं और \(A=\{-4,4\}\) है। इसलिए (n\(A^c\)=13-2=11) होगा।

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Mathematics Answer, Explanation and Revision Hints

यदि \(U={x:x\in\mathbb{Z},-6\le x\le 6}\) और \(A={x:x^2=16}\) है, तो (n\(A^c\)) कितना होगा? / If \(U={x:x\in\mathbb{Z},-6\le x\le 6}\) and \(A={x:x^2=16}\), what is (n\(A^c\))?

Correct Answer: A. (11). Explanation: (U) में (13) पूर्णांक हैं और \(A=\{-4,4\}\) है। इसलिए (n\(A^c\)=13-2=11) होगा। / There are (13) integers in (U), and \(A=\{-4,4\}\). Hence (n\(A^c\)=13-2=11).

Which concept should I revise for this Mathematics MCQ?

There are (13) integers in (U), and \(A=\{-4,4\}\). Hence (n\(A^c\)=13-2=11).

What exam hint can help solve this Mathematics question?

(U) में (13) पूर्णांक हैं और \(A=\{-4,4\}\) है। इसलिए (n\(A^c\)=13-2=11) होगा।