यदि \(U={x:x\in\mathbb{Z},-6\le x\le 6}\) और \(A={x:x^2=16}\) है, तो (n\(A^c\)) कितना होगा?
If \(U={x:x\in\mathbb{Z},-6\le x\le 6}\) and \(A={x:x^2=16}\), what is (n\(A^c\))?
Explanation opens after your attempt
A. (11)
Concept
There are (13) integers in (U), and \(A=\{-4,4\}\). Hence (n\(A^c\)=13-2=11).
Why this answer is correct
The correct answer is A. (11). There are (13) integers in (U), and \(A=\{-4,4\}\). Hence (n\(A^c\)=13-2=11).
Exam Tip
(U) में (13) पूर्णांक हैं और \(A=\{-4,4\}\) है। इसलिए (n\(A^c\)=13-2=11) होगा।
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