यदि \(U={x:x\in\mathbb{Z},-5\le x\le 5}\) और \(A={x:x^2=9}\) है, तो \(A^c\) में कितने तत्व होंगे?

If \(U={x:x\in\mathbb{Z},-5\le x\le 5}\) and \(A={x:x^2=9}\), how many elements are in \(A^c\)?

Explanation opens after your attempt
Correct Answer

A. (9)

Step 1

Concept

There are (11) integers in (U), and \(A=\{-3,3\}\). Hence (n\(A^c\)=11-2=9).

Step 2

Why this answer is correct

The correct answer is A. (9). There are (11) integers in (U), and \(A=\{-3,3\}\). Hence (n\(A^c\)=11-2=9).

Step 3

Exam Tip

(U) में (11) पूर्णांक हैं और \(A=\{-3,3\}\) है। इसलिए (n\(A^c\)=11-2=9) होगा।

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Mathematics Answer, Explanation and Revision Hints

यदि \(U={x:x\in\mathbb{Z},-5\le x\le 5}\) और \(A={x:x^2=9}\) है, तो \(A^c\) में कितने तत्व होंगे? / If \(U={x:x\in\mathbb{Z},-5\le x\le 5}\) and \(A={x:x^2=9}\), how many elements are in \(A^c\)?

Correct Answer: A. (9). Explanation: (U) में (11) पूर्णांक हैं और \(A=\{-3,3\}\) है। इसलिए (n\(A^c\)=11-2=9) होगा। / There are (11) integers in (U), and \(A=\{-3,3\}\). Hence (n\(A^c\)=11-2=9).

Which concept should I revise for this Mathematics MCQ?

There are (11) integers in (U), and \(A=\{-3,3\}\). Hence (n\(A^c\)=11-2=9).

What exam hint can help solve this Mathematics question?

(U) में (11) पूर्णांक हैं और \(A=\{-3,3\}\) है। इसलिए (n\(A^c\)=11-2=9) होगा।