\(यदि (U={x:x \in \mathbb{N},x\le 40}), (A={x:x \in U,x\) सम है\(}), (B={x:x \in U,x\) वर्ग संख्या है\(}), तो (n(A'\cap B')) क्या है\)?
\(If (U={x:x \in \mathbb{N},x\le 40}), (A={x:x \in U,x\) is even\(}), and (B={x:x \in U,x\) is a square number\(}), what is (n(A'\cap B'))\)?
Explanation opens after your attempt
Correct Answer
A. (17)
Concept
\(A'\cap B'\) means odd and non-square numbers. Among (20) odd numbers up to (40), (1,9,25) are squares, so (17) remain.
Why this answer is correct
The correct answer is A. (17). \(A'\cap B'\) means odd and non-square numbers. Among (20) odd numbers up to (40), (1,9,25) are squares, so (17) remain.
Exam Tip
\(A'\cap B'\) का अर्थ विषम और वर्ग नहीं संख्याएं हैं। (40) तक (20) विषम संख्याओं में (1,9,25) वर्ग हैं, इसलिए (17) बचते हैं।
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