यदि \(U={1,2,\ldots,96}\), (A) (6) के गुणजों का और (B) (10) के गुणजों का समुच्चय है, तो (n\(A\cup B\)) कितना है?
If \(U={1,2,\ldots,96}\), (A) is the set of multiples of (6) and (B) is the set of multiples of (10), then what is (n\(A\cup B\))?
Explanation opens after your attempt
Correct Answer
A. (23)
Concept
Multiples of (6) are (16), multiples of (10) are (9), and multiples of (30) are (3), so the union is (16+9-3=22). Check calculation before matching options.
Why this answer is correct
The correct answer is A. (23). Multiples of (6) are (16), multiples of (10) are (9), and multiples of (30) are (3), so the union is (16+9-3=22). Check calculation before matching options.
Exam Tip
(6) के गुणज (16), (10) के गुणज (9), और (30) के गुणज (3) हैं, इसलिए संघ (16+9-3=22) नहीं बल्कि (22) होगा; विकल्प मिलाते समय गणना जाँचें।
Login to save your score, XP, coins and progress.