यदि \(U={1,2,\ldots,9}\), \(A=\{1,2,3,4\}\) और \(B=\{3,4,5,6\}\), तो (\(A\cap B\)') क्या है?

If \(U={1,2,\ldots,9}\), \(A=\{1,2,3,4\}\), and \(B=\{3,4,5,6\}\), what is (\(A\cap B\)')?

Explanation opens after your attempt
Correct Answer

A. ({1,2,5,6,7,8,9})

Step 1

Concept

\(A\cap B={3,4}\), so its complement is all other elements in (U). For complement of an intersection, first find the common elements.

Step 2

Why this answer is correct

The correct answer is A. ({1,2,5,6,7,8,9}). \(A\cap B={3,4}\), so its complement is all other elements in (U). For complement of an intersection, first find the common elements.

Step 3

Exam Tip

\(A\cap B={3,4}\), इसलिए इसका पूरक (U) में बाकी सभी तत्व हैं। प्रतिच्छेद का पूरक लेते समय पहले साझा तत्व निकालें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(U={1,2,\ldots,9}\), \(A=\{1,2,3,4\}\) और \(B=\{3,4,5,6\}\), तो (\(A\cap B\)') क्या है? / If \(U={1,2,\ldots,9}\), \(A=\{1,2,3,4\}\), and \(B=\{3,4,5,6\}\), what is (\(A\cap B\)')?

Correct Answer: A. ({1,2,5,6,7,8,9}). Explanation: \(A\cap B={3,4}\), इसलिए इसका पूरक (U) में बाकी सभी तत्व हैं। प्रतिच्छेद का पूरक लेते समय पहले साझा तत्व निकालें। / \(A\cap B={3,4}\), so its complement is all other elements in (U). For complement of an intersection, first find the common elements.

Which concept should I revise for this Mathematics MCQ?

\(A\cap B={3,4}\), so its complement is all other elements in (U). For complement of an intersection, first find the common elements.

What exam hint can help solve this Mathematics question?

\(A\cap B={3,4}\), इसलिए इसका पूरक (U) में बाकी सभी तत्व हैं। प्रतिच्छेद का पूरक लेते समय पहले साझा तत्व निकालें।