\(यदि (U={1,2,\ldots,77}), (A={x:x\) 7 से विभाज्य है\(}) और (B={x:x\) 11 से विभाज्य है\(}), तो (|A'\cap B'|) कितना है\)?
\(If (U={1,2,\ldots,77}), (A={x:x\) is divisible by \(7}) and (B={x:x\) is divisible by \(11}), what is (|A'\cap B'|)\)?
Explanation opens after your attempt
Correct Answer
A. (60)
Concept
(|A|=11), (|B|=7), and \(|A\cap B|=1\), so \(|A\cup B|=17\). Hence \(|A'\cap B'|=77-17=60\).
Why this answer is correct
The correct answer is A. (60). (|A|=11), (|B|=7), and \(|A\cap B|=1\), so \(|A\cup B|=17\). Hence \(|A'\cap B'|=77-17=60\).
Exam Tip
(|A|=11), (|B|=7) और \(|A\cap B|=1\), इसलिए \(|A\cup B|=17\)। अतः \(|A'\cap B'|=77-17=60\)।
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