\(यदि (U={1,2,\ldots,55}), (A={x:x\) 5 से विभाज्य है\(}) और (B={x:x\) 11 से विभाज्य है\(}), तो (|A'\cap B'|) कितना है\)?
\(If (U={1,2,\ldots,55}), (A={x:x\) is divisible by \(5}) and (B={x:x\) is divisible by \(11}), what is (|A'\cap B'|)\)?
Explanation opens after your attempt
Correct Answer
C. (40)
Concept
(|A|=11), (|B|=5), and \(|A\cap B|=1\), so \(|A\cup B|=15\). Hence \(|A'\cap B'|=55-15=40\).
Why this answer is correct
The correct answer is C. (40). (|A|=11), (|B|=5), and \(|A\cap B|=1\), so \(|A\cup B|=15\). Hence \(|A'\cap B'|=55-15=40\).
Exam Tip
(|A|=11), (|B|=5) और \(|A\cap B|=1\), इसलिए \(|A\cup B|=15\)। अतः \(|A'\cap B'|=55-15=40\)।
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