यदि \(U={1,2,\ldots,54}\), \(A={x:x \in U,9\mid x}\), \(B={x:x \in U,6\mid x}\), तो (n\(A'\cap B'\)) क्या है?

If \(U={1,2,\ldots,54}\), \(A={x:x \in U,9\mid x}\), and \(B={x:x \in U,6\mid x}\), what is (n\(A'\cap B'\))?

Explanation opens after your attempt
Correct Answer

A. (42)

Step 1

Concept

(A'\cap B'=\(A\cup B\)'). Numbers divisible by (9) or (6) are (6+9-3=12), so the complement is (42).

Step 2

Why this answer is correct

The correct answer is A. (42). (A'\cap B'=\(A\cup B\)'). Numbers divisible by (9) or (6) are (6+9-3=12), so the complement is (42).

Step 3

Exam Tip

(A'\cap B'=\(A\cup B\)') है। (9) या (6) से विभाज्य संख्याएं (6+9-3=12) हैं, इसलिए पूरक (42) है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(U={1,2,\ldots,54}\), \(A={x:x \in U,9\mid x}\), \(B={x:x \in U,6\mid x}\), तो (n\(A'\cap B'\)) क्या है? / If \(U={1,2,\ldots,54}\), \(A={x:x \in U,9\mid x}\), and \(B={x:x \in U,6\mid x}\), what is (n\(A'\cap B'\))?

Correct Answer: A. (42). Explanation: (A'\cap B'=\(A\cup B\)') है। (9) या (6) से विभाज्य संख्याएं (6+9-3=12) हैं, इसलिए पूरक (42) है। / (A'\cap B'=\(A\cup B\)'). Numbers divisible by (9) or (6) are (6+9-3=12), so the complement is (42).

Which concept should I revise for this Mathematics MCQ?

(A'\cap B'=\(A\cup B\)'). Numbers divisible by (9) or (6) are (6+9-3=12), so the complement is (42).

What exam hint can help solve this Mathematics question?

(A'\cap B'=\(A\cup B\)') है। (9) या (6) से विभाज्य संख्याएं (6+9-3=12) हैं, इसलिए पूरक (42) है।