\(यदि (U={1,2,\ldots,16}), (A={x:x \in U,x\) वर्ग संख्या है\(}) और (B={x:x \in U,x\) विषम है\(}), तो (A'\cap B) क्या है\)?
\(If (U={1,2,\ldots,16}), (A={x:x \in U,x\) is a square number\(}), and (B={x:x \in U,x\) is odd\(}), what is (A'\cap B)\)?
Explanation opens after your attempt
Correct Answer
A. ({3,5,7,11,13,15})
Concept
From the odd numbers, the square numbers (1) and (9) are removed. Hence \(A'\cap B={3,5,7,11,13,15}\).
Why this answer is correct
The correct answer is A. ({3,5,7,11,13,15}). From the odd numbers, the square numbers (1) and (9) are removed. Hence \(A'\cap B={3,5,7,11,13,15}\).
Exam Tip
विषम संख्याओं में से वर्ग संख्याएं (1) और (9) हटेंगी। इसलिए \(A'\cap B={3,5,7,11,13,15}\) है।
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