यदि \(U={1,2,\ldots,15}\), \(A=\{3,6,9,12,15\}\), तो (n(\mathcal{P}(A'))) कितना है?
If \(U={1,2,\ldots,15}\), \(A=\{3,6,9,12,15\}\), what is (n(\mathcal{P}(A')))?
Explanation opens after your attempt
Correct Answer
A. (1024)
Concept
(A) has (5) elements and (U) has (15), so (A') has (10) elements. Therefore its power set has \(2^{10}=1024\) elements.
Why this answer is correct
The correct answer is A. (1024). (A) has (5) elements and (U) has (15), so (A') has (10) elements. Therefore its power set has \(2^{10}=1024\) elements.
Exam Tip
(A) में (5) तत्व हैं और (U) में (15), इसलिए (A') में (10) तत्व हैं। अतः घात समुच्चय में \(2^{10}=1024\) तत्व हैं।
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