\(यदि (U={1,2,3,\ldots,80}) और (A={x:x\) 8 से विभाज्य है\(}) है, तो (A^c) में कितने तत्व होंगे\)?
\(If (U={1,2,3,\ldots,80}) and (A={x:x\) is divisible by \(8}), how many elements are in (A^c)\)?
Explanation opens after your attempt
A. (70)
Concept
There are (10) multiples of (8) from (1) to (80). Therefore the complement has (80-10=70) elements.
Why this answer is correct
The correct answer is A. (70). There are (10) multiples of (8) from (1) to (80). Therefore the complement has (80-10=70) elements.
Exam Tip
(1) से (80) तक (8) के (10) गुणज हैं। इसलिए पूरक में (80-10=70) तत्व होंगे।
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