यदि \(U=\{1,2,3,4,5,6,7,8,9,10\}\), \(A=\{1,2,3,4,5\}\) और \(B=\{2,4,6,8,10\}\), तो \(A'\cup B'\) में कितने तत्व हैं?

If \(U=\{1,2,3,4,5,6,7,8,9,10\}\), \(A=\{1,2,3,4,5\}\) and \(B=\{2,4,6,8,10\}\), how many elements are in \(A'\cup B'\)?

Explanation opens after your attempt
Correct Answer

C. (8)

Step 1

Concept

By De Morgan's law, (A'\cup B'=\(A\cap B\)'). Since \(A\cap B={2,4}\), the complement has (10-2=8) elements.

Step 2

Why this answer is correct

The correct answer is C. (8). By De Morgan's law, (A'\cup B'=\(A\cap B\)'). Since \(A\cap B={2,4}\), the complement has (10-2=8) elements.

Step 3

Exam Tip

डी मॉर्गन से (A'\cup B'=\(A\cap B\)') होता है। \(A\cap B={2,4}\), इसलिए पूरक में (10-2=8) तत्व हैं।

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Mathematics Answer, Explanation and Revision Hints

यदि \(U=\{1,2,3,4,5,6,7,8,9,10\}\), \(A=\{1,2,3,4,5\}\) और \(B=\{2,4,6,8,10\}\), तो \(A'\cup B'\) में कितने तत्व हैं? / If \(U=\{1,2,3,4,5,6,7,8,9,10\}\), \(A=\{1,2,3,4,5\}\) and \(B=\{2,4,6,8,10\}\), how many elements are in \(A'\cup B'\)?

Correct Answer: C. (8). Explanation: डी मॉर्गन से (A'\cup B'=\(A\cap B\)') होता है। \(A\cap B={2,4}\), इसलिए पूरक में (10-2=8) तत्व हैं। / By De Morgan's law, (A'\cup B'=\(A\cap B\)'). Since \(A\cap B={2,4}\), the complement has (10-2=8) elements.

Which concept should I revise for this Mathematics MCQ?

By De Morgan's law, (A'\cup B'=\(A\cap B\)'). Since \(A\cap B={2,4}\), the complement has (10-2=8) elements.

What exam hint can help solve this Mathematics question?

डी मॉर्गन से (A'\cup B'=\(A\cap B\)') होता है। \(A\cap B={2,4}\), इसलिए पूरक में (10-2=8) तत्व हैं।