यदि (n(U)=250), (n(A)=120), (n(B)=110), (n(C)=95), (n\(A\cap B\)=52), (n\(B\cap C\)=41), (n\(C\cap A\)=37), (n\(A\cap B\cap C\)=19) है, तो कम से कम एक में नहीं होने वालों की संख्या क्या है?
If (n(U)=250), (n(A)=120), (n(B)=110), (n(C)=95), (n\(A\cap B\)=52), (n\(B\cap C\)=41), (n\(C\cap A\)=37), and (n\(A\cap B\cap C\)=19), what is the number not in at least one set?
Explanation opens after your attempt
Correct Answer
A. (36)
Concept
The union for at least one is (120+110+95-52-41-37+19=214), so outside is (250-214=36). With large numbers, write the formula in order.
Why this answer is correct
The correct answer is A. (36). The union for at least one is (120+110+95-52-41-37+19=214), so outside is (250-214=36). With large numbers, write the formula in order.
Exam Tip
कम से कम एक का संघ (120+110+95-52-41-37+19=214) है, इसलिए बाहर (250-214=36)। लंबी संख्याओं में सूत्र क्रम से लिखें।
Login to save your score, XP, coins and progress.