यदि (n(U)=200), (n(A')=76), (n(B')=89) और (n\(A'\cap B'\)=31), तो (n(\(A\cap B\)')) क्या है?
If (n(U)=200), (n(A')=76), (n(B')=89), and (n\(A'\cap B'\)=31), what is (n(\(A\cap B\)'))?
Explanation opens after your attempt
A. (134)
Concept
By De Morgan, (\(A\cap B\)'=A'\cup B'). Thus (n\(A'\cup B'\)=76+89-31=134).
Why this answer is correct
The correct answer is A. (134). By De Morgan, (\(A\cap B\)'=A'\cup B'). Thus (n\(A'\cup B'\)=76+89-31=134).
Exam Tip
डी मॉर्गन से (\(A\cap B\)'=A'\cup B')। इसलिए (n\(A'\cup B'\)=76+89-31=134) है।
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