यदि (n(U)=110), (n(A)=58), (n(B)=47), और (n\(A\cap B\)=20), तो (n(\(A\cup B\)')) क्या है?
If (n(U)=110), (n(A)=58), (n(B)=47), and (n\(A\cap B\)=20), what is (n(\(A\cup B\)'))?
Explanation opens after your attempt
A. (25)
Concept
First (n\(A\cup B\)=58+47-20=85). Therefore, (n(\(A\cup B\)')=110-85=25).
Why this answer is correct
The correct answer is A. (25). First (n\(A\cup B\)=58+47-20=85). Therefore, (n(\(A\cup B\)')=110-85=25).
Exam Tip
पहले (n\(A\cup B\)=58+47-20=85)। इसलिए (n(\(A\cup B\)')=110-85=25)।
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