यदि \(^{n}C_{3}=4,^{n}C_{2}\) है, तो (n) का मान क्या है?

If \(^{n}C_{3}=4,^{n}C_{2}\), what is the value of (n)?

Explanation opens after your attempt
Correct Answer

B. (14)

Step 1

Concept

The ratio is \(\frac{^{n}C_{3}}{^{n}C_{2}}=\frac{n-2}{3}\), so (n=14). In exams write the ratio first.

Step 2

Why this answer is correct

The correct answer is B. (14). The ratio is \(\frac{^{n}C_{3}}{^{n}C_{2}}=\frac{n-2}{3}\), so (n=14). In exams write the ratio first.

Step 3

Exam Tip

अनुपात \(\frac{^{n}C_{3}}{^{n}C_{2}}=\frac{n-2}{3}\) होगा, इसलिए (n=14)। परीक्षा में पहले अनुपात लिखें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(^{n}C_{3}=4,^{n}C_{2}\) है, तो (n) का मान क्या है? / If \(^{n}C_{3}=4,^{n}C_{2}\), what is the value of (n)?

Correct Answer: B. (14). Explanation: अनुपात \(\frac{^{n}C_{3}}{^{n}C_{2}}=\frac{n-2}{3}\) होगा, इसलिए (n=14)। परीक्षा में पहले अनुपात लिखें। / The ratio is \(\frac{^{n}C_{3}}{^{n}C_{2}}=\frac{n-2}{3}\), so (n=14). In exams write the ratio first.

Which concept should I revise for this Mathematics MCQ?

The ratio is \(\frac{^{n}C_{3}}{^{n}C_{2}}=\frac{n-2}{3}\), so (n=14). In exams write the ratio first.

What exam hint can help solve this Mathematics question?

अनुपात \(\frac{^{n}C_{3}}{^{n}C_{2}}=\frac{n-2}{3}\) होगा, इसलिए (n=14)। परीक्षा में पहले अनुपात लिखें।