यदि (n\(A\cup B\cup C\)=100), (n(A)=50), (n(B)=45), (n(C)=40), (n\(A\cap B\)=18), (n\(B\cap C\)=15), (n\(C\cap A\)=12) है, तो (n\(A\cap B\cap C\)) क्या है?
If (n\(A\cup B\cup C\)=100), (n(A)=50), (n(B)=45), (n(C)=40), (n\(A\cap B\)=18), (n\(B\cap C\)=15), and (n\(C\cap A\)=12), what is (n\(A\cap B\cap C\))?
Explanation opens after your attempt
A. (10)
Concept
In the formula, (100=50+45+40-18-15-12+x), so (x=10). Take the unknown triple intersection as (x) and solve.
Why this answer is correct
The correct answer is A. (10). In the formula, (100=50+45+40-18-15-12+x), so (x=10). Take the unknown triple intersection as (x) and solve.
Exam Tip
सूत्र में (100=50+45+40-18-15-12+x), इसलिए (x=10)। अज्ञात त्रिक छेदन को (x) मानकर हल करें।
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