यदि (n\(A\cup B\cup C\)=100), (n(A)=50), (n(B)=45), (n(C)=40), (n\(A\cap B\)=18), (n\(B\cap C\)=15), (n\(C\cap A\)=12) है, तो (n\(A\cap B\cap C\)) क्या है?

If (n\(A\cup B\cup C\)=100), (n(A)=50), (n(B)=45), (n(C)=40), (n\(A\cap B\)=18), (n\(B\cap C\)=15), and (n\(C\cap A\)=12), what is (n\(A\cap B\cap C\))?

Explanation opens after your attempt
Correct Answer

A. (10)

Step 1

Concept

In the formula, (100=50+45+40-18-15-12+x), so (x=10). Take the unknown triple intersection as (x) and solve.

Step 2

Why this answer is correct

The correct answer is A. (10). In the formula, (100=50+45+40-18-15-12+x), so (x=10). Take the unknown triple intersection as (x) and solve.

Step 3

Exam Tip

सूत्र में (100=50+45+40-18-15-12+x), इसलिए (x=10)। अज्ञात त्रिक छेदन को (x) मानकर हल करें।

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Mathematics Answer, Explanation and Revision Hints

यदि (n\(A\cup B\cup C\)=100), (n(A)=50), (n(B)=45), (n(C)=40), (n\(A\cap B\)=18), (n\(B\cap C\)=15), (n\(C\cap A\)=12) है, तो (n\(A\cap B\cap C\)) क्या है? / If (n\(A\cup B\cup C\)=100), (n(A)=50), (n(B)=45), (n(C)=40), (n\(A\cap B\)=18), (n\(B\cap C\)=15), and (n\(C\cap A\)=12), what is (n\(A\cap B\cap C\))?

Correct Answer: A. (10). Explanation: सूत्र में (100=50+45+40-18-15-12+x), इसलिए (x=10)। अज्ञात त्रिक छेदन को (x) मानकर हल करें। / In the formula, (100=50+45+40-18-15-12+x), so (x=10). Take the unknown triple intersection as (x) and solve.

Which concept should I revise for this Mathematics MCQ?

In the formula, (100=50+45+40-18-15-12+x), so (x=10). Take the unknown triple intersection as (x) and solve.

What exam hint can help solve this Mathematics question?

सूत्र में (100=50+45+40-18-15-12+x), इसलिए (x=10)। अज्ञात त्रिक छेदन को (x) मानकर हल करें।