यदि (n\(A\cup B\)=98) और (n\(A\cap B\)=35) है, तो (n(A-B)+n(B-A)) कितना होगा?
If (n\(A\cup B\)=98) and (n\(A\cap B\)=35), then what is (n(A-B)+n(B-A))?
Explanation opens after your attempt
A. (63)
Concept
The sum of the two only regions is (98-35=63). This is also the size of \(A\triangle B\).
Why this answer is correct
The correct answer is A. (63). The sum of the two only regions is (98-35=63). This is also the size of \(A\triangle B\).
Exam Tip
दोनों केवल क्षेत्रों का योग (98-35=63) है। यह \(A\triangle B\) की संख्या भी होती है।
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