यदि (n\(A\cap B\)=20), (n\(B\cap C\)=18), (n\(C\cap A\)=16) और (n\(A\cap B\cap C\)=6) है, तो ठीक दो समुच्चयों में कितने तत्व हैं?

If (n\(A\cap B\)=20), (n\(B\cap C\)=18), (n\(C\cap A\)=16), and (n\(A\cap B\cap C\)=6), how many elements are in exactly two sets?

Explanation opens after your attempt
Correct Answer

A. (36)

Step 1

Concept

Exactly two is \(20+18+16-3\cdot6=36\). The triple part is counted repeatedly in pairwise intersections.

Step 2

Why this answer is correct

The correct answer is A. (36). Exactly two is \(20+18+16-3\cdot6=36\). The triple part is counted repeatedly in pairwise intersections.

Step 3

Exam Tip

ठीक दो \(=20+18+16-3\cdot6=36\)। युग्म छेदनों में त्रिक भाग बार-बार गिना जाता है।

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Mathematics Answer, Explanation and Revision Hints

यदि (n\(A\cap B\)=20), (n\(B\cap C\)=18), (n\(C\cap A\)=16) और (n\(A\cap B\cap C\)=6) है, तो ठीक दो समुच्चयों में कितने तत्व हैं? / If (n\(A\cap B\)=20), (n\(B\cap C\)=18), (n\(C\cap A\)=16), and (n\(A\cap B\cap C\)=6), how many elements are in exactly two sets?

Correct Answer: A. (36). Explanation: ठीक दो \(=20+18+16-3\cdot6=36\)। युग्म छेदनों में त्रिक भाग बार-बार गिना जाता है। / Exactly two is \(20+18+16-3\cdot6=36\). The triple part is counted repeatedly in pairwise intersections.

Which concept should I revise for this Mathematics MCQ?

Exactly two is \(20+18+16-3\cdot6=36\). The triple part is counted repeatedly in pairwise intersections.

What exam hint can help solve this Mathematics question?

ठीक दो \(=20+18+16-3\cdot6=36\)। युग्म छेदनों में त्रिक भाग बार-बार गिना जाता है।