यदि (n(A-B)=3x+2), (n(B-A)=2x+5), (n\(A\cap B\)=x+4) और (n\(A\cup B\)=71) है, तो (x) कितना है?
If (n(A-B)=3x+2), (n(B-A)=2x+5), (n\(A\cap B\)=x+4) and (n\(A\cup B\)=71), then what is (x)?
Explanation opens after your attempt
A. (10)
Concept
The union is (3x+2+2x+5+x+4=6x+11=71), so (x=10). The sum of disjoint regions directly gives the union.
Why this answer is correct
The correct answer is A. (10). The union is (3x+2+2x+5+x+4=6x+11=71), so (x=10). The sum of disjoint regions directly gives the union.
Exam Tip
संघ (3x+2+2x+5+x+4=6x+11=71), इसलिए (x=10) है। अलग क्षेत्रों का योग सीधे संघ देता है।
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