यदि (n(A)=5), (n(B)=4) और (n\(A\cap B\)=2) हैं, तो (n\(A\cup B\)) क्या होगा?

If (n(A)=5), (n(B)=4), and (n\(A\cap B\)=2), what will (n\(A\cup B\)) be?

Explanation opens after your attempt
Correct Answer

A. (7)

Step 1

Concept

Use (n\(A\cup B\)=n(A)+n(B)-n\(A\cap B\)). Thus (5+4-2=7).

Step 2

Why this answer is correct

The correct answer is A. (7). Use (n\(A\cup B\)=n(A)+n(B)-n\(A\cap B\)). Thus (5+4-2=7).

Step 3

Exam Tip

सूत्र (n\(A\cup B\)=n(A)+n(B)-n\(A\cap B\)) लगाएं। इसलिए (5+4-2=7) है।

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Mathematics Answer, Explanation and Revision Hints

यदि (n(A)=5), (n(B)=4) और (n\(A\cap B\)=2) हैं, तो (n\(A\cup B\)) क्या होगा? / If (n(A)=5), (n(B)=4), and (n\(A\cap B\)=2), what will (n\(A\cup B\)) be?

Correct Answer: A. (7). Explanation: सूत्र (n\(A\cup B\)=n(A)+n(B)-n\(A\cap B\)) लगाएं। इसलिए (5+4-2=7) है। / Use (n\(A\cup B\)=n(A)+n(B)-n\(A\cap B\)). Thus (5+4-2=7).

Which concept should I revise for this Mathematics MCQ?

Use (n\(A\cup B\)=n(A)+n(B)-n\(A\cap B\)). Thus (5+4-2=7).

What exam hint can help solve this Mathematics question?

सूत्र (n\(A\cup B\)=n(A)+n(B)-n\(A\cap B\)) लगाएं। इसलिए (5+4-2=7) है।