यदि (n(A)=4x+6), (n(B)=3x+9), (n\(A\cap B\)=2x+5) और (n\(A\cup B\)=80) है, तो (x) का मान ज्ञात कीजिए।

If (n(A)=4x+6), (n(B)=3x+9), (n\(A\cap B\)=2x+5), and (n\(A\cup B\)=80), find (x).

Explanation opens after your attempt
Correct Answer

A. (14)

Step 1

Concept

From ((4x+6)+(3x+9)-(2x+5)=80), (5x+10=80), so (x=14). Do not forget to subtract the intersection.

Step 2

Why this answer is correct

The correct answer is A. (14). From ((4x+6)+(3x+9)-(2x+5)=80), (5x+10=80), so (x=14). Do not forget to subtract the intersection.

Step 3

Exam Tip

((4x+6)+(3x+9)-(2x+5)=80) से (5x+10=80), इसलिए (x=14)। सूत्र लगाते समय छेदन घटाना न भूलें।

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यदि (n(A)=4x+6), (n(B)=3x+9), (n\(A\cap B\)=2x+5) और (n\(A\cup B\)=80) है, तो (x) का मान ज्ञात कीजिए। / If (n(A)=4x+6), (n(B)=3x+9), (n\(A\cap B\)=2x+5), and (n\(A\cup B\)=80), find (x).

Correct Answer: A. (14). Explanation: ((4x+6)+(3x+9)-(2x+5)=80) से (5x+10=80), इसलिए (x=14)। सूत्र लगाते समय छेदन घटाना न भूलें। / From ((4x+6)+(3x+9)-(2x+5)=80), (5x+10=80), so (x=14). Do not forget to subtract the intersection.

Which concept should I revise for this Mathematics MCQ?

From ((4x+6)+(3x+9)-(2x+5)=80), (5x+10=80), so (x=14). Do not forget to subtract the intersection.

What exam hint can help solve this Mathematics question?

((4x+6)+(3x+9)-(2x+5)=80) से (5x+10=80), इसलिए (x=14)। सूत्र लगाते समय छेदन घटाना न भूलें।