यदि (n(A)=28), (n(B)=30), और केवल (B) में (21) अवयव हैं, तो (n\(A\cap B\)) क्या है?

If (n(A)=28), (n(B)=30), and only (B) has (21) elements, what is (n\(A\cap B\))?

Explanation opens after your attempt
Correct Answer

B. (9)

Step 1

Concept

Out of total (30) elements of (B), only (B) has (21). Therefore, the common part is (30-21=9).

Step 2

Why this answer is correct

The correct answer is B. (9). Out of total (30) elements of (B), only (B) has (21). Therefore, the common part is (30-21=9).

Step 3

Exam Tip

(B) के कुल (30) में केवल (B) (21) है। इसलिए साझा भाग (30-21=9) है।

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Mathematics Answer, Explanation and Revision Hints

यदि (n(A)=28), (n(B)=30), और केवल (B) में (21) अवयव हैं, तो (n\(A\cap B\)) क्या है? / If (n(A)=28), (n(B)=30), and only (B) has (21) elements, what is (n\(A\cap B\))?

Correct Answer: B. (9). Explanation: (B) के कुल (30) में केवल (B) (21) है। इसलिए साझा भाग (30-21=9) है। / Out of total (30) elements of (B), only (B) has (21). Therefore, the common part is (30-21=9).

Which concept should I revise for this Mathematics MCQ?

Out of total (30) elements of (B), only (B) has (21). Therefore, the common part is (30-21=9).

What exam hint can help solve this Mathematics question?

(B) के कुल (30) में केवल (B) (21) है। इसलिए साझा भाग (30-21=9) है।