यदि (|\mathcal{P}(A)|=32) और (|\mathcal{P}(B)|=8), तो (|\mathcal{P}\(A\times B\)|) क्या है?

If (|\mathcal{P}(A)|=32) and (|\mathcal{P}(B)|=8), what is (|\mathcal{P}\(A\times B\)|)?

Explanation opens after your attempt
Correct Answer

A. \(2^{15}\)

Step 1

Concept

(|A|=5) and (|B|=3), so \(|A\times B|=15\). Therefore its power set has \(2^{15}\) elements.

Step 2

Why this answer is correct

The correct answer is A. \(2^{15}\). (|A|=5) and (|B|=3), so \(|A\times B|=15\). Therefore its power set has \(2^{15}\) elements.

Step 3

Exam Tip

(|A|=5) और (|B|=3), इसलिए \(|A\times B|=15\) है। अतः उसके घात समुच्चय में \(2^{15}\) तत्व होंगे।

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Mathematics Answer, Explanation and Revision Hints

यदि (|\mathcal{P}(A)|=32) और (|\mathcal{P}(B)|=8), तो (|\mathcal{P}\(A\times B\)|) क्या है? / If (|\mathcal{P}(A)|=32) and (|\mathcal{P}(B)|=8), what is (|\mathcal{P}\(A\times B\)|)?

Correct Answer: A. \(2^{15}\). Explanation: (|A|=5) और (|B|=3), इसलिए \(|A\times B|=15\) है। अतः उसके घात समुच्चय में \(2^{15}\) तत्व होंगे। / (|A|=5) and (|B|=3), so \(|A\times B|=15\). Therefore its power set has \(2^{15}\) elements.

Which concept should I revise for this Mathematics MCQ?

(|A|=5) and (|B|=3), so \(|A\times B|=15\). Therefore its power set has \(2^{15}\) elements.

What exam hint can help solve this Mathematics question?

(|A|=5) और (|B|=3), इसलिए \(|A\times B|=15\) है। अतः उसके घात समुच्चय में \(2^{15}\) तत्व होंगे।