Class 11 Mathematics Permutations and Combinations Factorial notation Hard Level 56

यदि ( \frac{n!}{(n-3)!}=336 ), तो (n) का धनात्मक मान क्या है?

If ( \frac{n!}{(n-3)!}=336 ), what is the positive value of (n)?

Explanation opens after your attempt
Correct Answer

C. (8)

Step 1

Concept

It is (n(n-1)(n-2)=336), and \(8\cdot7\cdot6=336\). In such questions, look for three consecutive decreasing factors.

Step 2

Why this answer is correct

The correct answer is C. (8). It is (n(n-1)(n-2)=336), and \(8\cdot7\cdot6=336\). In such questions, look for three consecutive decreasing factors.

Step 3

Exam Tip

यह (n(n-1)(n-2)=336) है और \(8\cdot7\cdot6=336\)। ऐसे प्रश्नों में तीन लगातार घटते गुणक देखें।

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यदि ( \frac{n!}{(n-3)!}=336 ), तो (n) का धनात्मक मान क्या है? / If ( \frac{n!}{(n-3)!}=336 ), what is the positive value of (n)?

Correct Answer: C. (8). Explanation: यह (n(n-1)(n-2)=336) है और \(8\cdot7\cdot6=336\)। ऐसे प्रश्नों में तीन लगातार घटते गुणक देखें। / It is (n(n-1)(n-2)=336), and \(8\cdot7\cdot6=336\). In such questions, look for three consecutive decreasing factors.

Which concept should I revise for this Mathematics MCQ?

It is (n(n-1)(n-2)=336), and \(8\cdot7\cdot6=336\). In such questions, look for three consecutive decreasing factors.

What exam hint can help solve this Mathematics question?

यह (n(n-1)(n-2)=336) है और \(8\cdot7\cdot6=336\)। ऐसे प्रश्नों में तीन लगातार घटते गुणक देखें।