यदि (\frac{n!}{(n-2)!}=132) है तो (n) का मान क्या है?
If (\frac{n!}{(n-2)!}=132) then what is the value of (n)?
Explanation opens after your attempt
C. (12)
Concept
The equation becomes (n(n-1)=132). Since \(12\times11=132\), (n=12).
Why this answer is correct
The correct answer is C. (12). The equation becomes (n(n-1)=132). Since \(12\times11=132\), (n=12).
Exam Tip
समीकरण (n(n-1)=132) बनता है। \(12\times11=132\) इसलिए (n=12) है।
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