यदि ( \frac{(n+5)!}{(n+2)!}=1320 ), तो (n) का मान क्या है?
If ( \frac{(n+5)!}{(n+2)!}=1320 ), what is the value of (n)?
Explanation opens after your attempt
C. (8)
Concept
It is ((n+5)(n+4)(n+3)=1320). Since \(12\cdot11\cdot10=1320\), (n=7).
Why this answer is correct
The correct answer is C. (8). It is ((n+5)(n+4)(n+3)=1320). Since \(12\cdot11\cdot10=1320\), (n=7).
Exam Tip
यह ((n+5)(n+4)(n+3)=1320) है और \(13\cdot12\cdot11=1716\) नहीं; \(12\cdot11\cdot10=1320\), इसलिए (n=7)।
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