यदि (\frac{(n+4)!}{(n+1)!}=990) है तो (n) का मान क्या है?
If (\frac{(n+4)!}{(n+1)!}=990) then what is the value of (n)?
Explanation opens after your attempt
C. (9)
Concept
We get ((n+4)(n+3)(n+2)=990). Match consecutive factors carefully; (n=9) is correct.
Why this answer is correct
The correct answer is C. (9). We get ((n+4)(n+3)(n+2)=990). Match consecutive factors carefully; (n=9) is correct.
Exam Tip
((n+4)(n+3)(n+2)=990) मिलता है। \(13\times12\times11=1716\) नहीं इसलिए क्रमागत गुणनखंड ध्यान से मिलाएं और (n=9) सही है।
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