यदि ( \frac{(n+3)!}{n!}-\frac{(n+2)!}{(n-1)!}=216 ), तो (n) का मान क्या है?
If ( \frac{(n+3)!}{n!}-\frac{(n+2)!}{(n-1)!}=216 ), what is the value of (n)?
Explanation opens after your attempt
Correct Answer
A. (6)
Concept
The simplified form is (3(n+1)(n+2)), so ((n+1)(n+2)=72) and (n=7); the correct option is (7). First simplify and then match options.
Why this answer is correct
The correct answer is A. (6). The simplified form is (3(n+1)(n+2)), so ((n+1)(n+2)=72) and (n=7); the correct option is (7). First simplify and then match options.
Exam Tip
सरल रूप (3(n+1)(n+2)) है, इसलिए ((n+1)(n+2)=72) और (n=7) होगा; सही विकल्प (7) है। पहले रूप निकालकर विकल्प मिलाएं।
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