यदि ( \frac{(n+2)!}{(n-2)!}=5040 ), तो (n) का मान क्या है?
If ( \frac{(n+2)!}{(n-2)!}=5040 ), what is the value of (n)?
Explanation opens after your attempt
B. (8)
Concept
It is ((n+2)(n+1)n(n-1)=5040). Since \(10\cdot9\cdot8\cdot7=5040\), (n=8).
Why this answer is correct
The correct answer is B. (8). It is ((n+2)(n+1)n(n-1)=5040). Since \(10\cdot9\cdot8\cdot7=5040\), (n=8).
Exam Tip
यह ((n+2)(n+1)n(n-1)=5040) है। \(10\cdot9\cdot8\cdot7=5040\), इसलिए (n=8)।
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