यदि \(\frac{(n+2)!}{(n-2)!}=3024\), तो (n) का मान क्या है?

If \(\frac{(n+2)!}{(n-2)!}=3024 \), what is the value of (n)?

Explanation opens after your attempt
Correct Answer

B. (7)

Step 1

Concept

It is \((n+2)(n+1)n(n-1)=3024\). Since \(9\cdot8\cdot7\cdot6=3024\), (n=7).

Step 2

Why this answer is correct

The correct answer is B. (7). It is \((n+2)(n+1)n(n-1)=3024\). Since \(9\cdot8\cdot7\cdot6=3024\), (n=7).

Step 3

Exam Tip

यह \((n+2)(n+1)n(n-1)=3024\) है। \(9\cdot8\cdot7\cdot6=3024\), इसलिए (n=7)।

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Mathematics Answer, Explanation and Revision Hints

यदि \(\frac{(n+2)!}{(n-2)!}=3024\), तो (n) का मान क्या है? / If \(\frac{(n+2)!}{(n-2)!}=3024 \), what is the value of (n)?

Correct Answer: B. (7). Explanation: यह \((n+2)(n+1)n(n-1)=3024\) है। \(9\cdot8\cdot7\cdot6=3024\), इसलिए (n=7)। / It is \((n+2)(n+1)n(n-1)=3024\). Since \(9\cdot8\cdot7\cdot6=3024\), (n=7).

Which concept should I revise for this Mathematics MCQ?

It is \((n+2)(n+1)n(n-1)=3024\). Since \(9\cdot8\cdot7\cdot6=3024\), (n=7).

What exam hint can help solve this Mathematics question?

यह \((n+2)(n+1)n(n-1)=3024\) है। \(9\cdot8\cdot7\cdot6=3024\), इसलिए (n=7)।