यदि ( \frac{(n!)2}{(n-1)!(n+1)!}=\frac{5}{6} ), तो (n) का मान क्या है?
If ( \frac{(n!)2}{(n-1)!(n+1)!}=\frac{5}{6} ), what is the value of (n)?
Explanation opens after your attempt
Correct Answer
A. (5)
Concept
The simplified form is \( \frac{n}{n+1} \), so \( \frac{n}{n+1}=\frac{5}{6} \). This gives (n=5).
Why this answer is correct
The correct answer is A. (5). The simplified form is \( \frac{n}{n+1} \), so \( \frac{n}{n+1}=\frac{5}{6} \). This gives (n=5).
Exam Tip
सरल रूप \( \frac{n}{n+1} \) है, इसलिए \( \frac{n}{n+1}=\frac{5}{6} \)। इससे (n=5) मिलता है।
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