यदि ( \frac{(n+1)!+n!}{(n-1)!}=63 ), तो (n) का मान क्या होगा?

If ( \frac{(n+1)!+n!}{(n-1)!}=63 ), what will be the value of (n)?

Explanation opens after your attempt
Correct Answer

C. (7)

Step 1

Concept

The simplified form is (n(n+2)), so (n(n+2)=63). Since \(7\cdot9=63\), (n=7).

Step 2

Why this answer is correct

The correct answer is C. (7). The simplified form is (n(n+2)), so (n(n+2)=63). Since \(7\cdot9=63\), (n=7).

Step 3

Exam Tip

सरल रूप (n(n+2)) है, इसलिए (n(n+2)=63)। \(7\cdot9=63\), इसलिए (n=7)।

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Mathematics Answer, Explanation and Revision Hints

यदि ( \frac{(n+1)!+n!}{(n-1)!}=63 ), तो (n) का मान क्या होगा? / If ( \frac{(n+1)!+n!}{(n-1)!}=63 ), what will be the value of (n)?

Correct Answer: C. (7). Explanation: सरल रूप (n(n+2)) है, इसलिए (n(n+2)=63)। \(7\cdot9=63\), इसलिए (n=7)। / The simplified form is (n(n+2)), so (n(n+2)=63). Since \(7\cdot9=63\), (n=7).

Which concept should I revise for this Mathematics MCQ?

The simplified form is (n(n+2)), so (n(n+2)=63). Since \(7\cdot9=63\), (n=7).

What exam hint can help solve this Mathematics question?

सरल रूप (n(n+2)) है, इसलिए (n(n+2)=63)। \(7\cdot9=63\), इसलिए (n=7)।