यदि ( \frac{(n+1)!+n!}{(n-1)!}=63 ), तो (n) का मान क्या होगा?
If ( \frac{(n+1)!+n!}{(n-1)!}=63 ), what will be the value of (n)?
Explanation opens after your attempt
C. (7)
Concept
The simplified form is (n(n+2)), so (n(n+2)=63). Since \(7\cdot9=63\), (n=7).
Why this answer is correct
The correct answer is C. (7). The simplified form is (n(n+2)), so (n(n+2)=63). Since \(7\cdot9=63\), (n=7).
Exam Tip
सरल रूप (n(n+2)) है, इसलिए (n(n+2)=63)। \(7\cdot9=63\), इसलिए (n=7)।
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