यदि ( \frac{(n+1)!}{(n-1)!}-\frac{n!}{(n-2)!}=18 ), तो (n) का मान क्या है?
If ( \frac{(n+1)!}{(n-1)!}-\frac{n!}{(n-2)!}=18 ), what is the value of (n)?
Explanation opens after your attempt
B. (9)
Concept
The simplified form is (2n), so (2n=18). Hence (n=9).
Why this answer is correct
The correct answer is B. (9). The simplified form is (2n), so (2n=18). Hence (n=9).
Exam Tip
सरल रूप (2n) है, इसलिए (2n=18)। अतः (n=9)।
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