यदि ( \frac{\frac{(n+3)!}{(n-2)!}}{\frac{(n+2)!}{(n-3)!}}=\frac{5}{2} ), तो (n) का मान क्या है?
If ( \frac{\frac{(n+3)!}{(n-2)!}}{\frac{(n+2)!}{(n-3)!}}=\frac{5}{2} ), what is the value of (n)?
Explanation opens after your attempt
Correct Answer
B. (4)
Concept
The simplified form is \( \frac{n+3}{n-2} \). From \( \frac{n+3}{n-2}=\frac{5}{2} \), we get (n=4).
Why this answer is correct
The correct answer is B. (4). The simplified form is \( \frac{n+3}{n-2} \). From \( \frac{n+3}{n-2}=\frac{5}{2} \), we get (n=4).
Exam Tip
सरल रूप \( \frac{n+3}{n-2} \) है। \( \frac{n+3}{n-2}=\frac{5}{2} \) से (n=4) मिलता है।
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