यदि ( \frac{(4n+1)!}{(4n-1)!}=420 ), तो (n) का मान क्या है?

If ( \frac{(4n+1)!}{(4n-1)!}=420 ), what is the value of (n)?

Explanation opens after your attempt
Correct Answer

B. (5)

Step 1

Concept

It is ((4n+1)(4n)=420). Since \(21\cdot20=420\), (4n=20) and (n=5).

Step 2

Why this answer is correct

The correct answer is B. (5). It is ((4n+1)(4n)=420). Since \(21\cdot20=420\), (4n=20) and (n=5).

Step 3

Exam Tip

यह ((4n+1)(4n)=420) है। \(21\cdot20=420\), इसलिए (4n=20) और (n=5)।

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Mathematics Answer, Explanation and Revision Hints

यदि ( \frac{(4n+1)!}{(4n-1)!}=420 ), तो (n) का मान क्या है? / If ( \frac{(4n+1)!}{(4n-1)!}=420 ), what is the value of (n)?

Correct Answer: B. (5). Explanation: यह ((4n+1)(4n)=420) है। \(21\cdot20=420\), इसलिए (4n=20) और (n=5)। / It is ((4n+1)(4n)=420). Since \(21\cdot20=420\), (4n=20) and (n=5).

Which concept should I revise for this Mathematics MCQ?

It is ((4n+1)(4n)=420). Since \(21\cdot20=420\), (4n=20) and (n=5).

What exam hint can help solve this Mathematics question?

यह ((4n+1)(4n)=420) है। \(21\cdot20=420\), इसलिए (4n=20) और (n=5)।