यदि (f(x)=x+\frac{1}{x}) और \(x\ne 0\), तो (f) का परिसर क्या है?
If (f(x)=x+\frac{1}{x}) and \(x\ne 0\), what is the range of (f)?
Explanation opens after your attempt
A. ( \(-\infty,-2]\cup[2,\infty\) )
Concept
For positive (x), the value is at least (2), and for negative (x), it is at most (-2). Check both cases separately.
Why this answer is correct
The correct answer is A. ( \(-\infty,-2]\cup[2,\infty\) ). For positive (x), the value is at least (2), and for negative (x), it is at most (-2). Check both cases separately.
Exam Tip
धनात्मक (x) पर मान कम से कम (2) और ऋणात्मक (x) पर अधिक से अधिक (-2) होता है। दोनों स्थितियों को अलग जांचें।
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