यदि (f(x)=x+\frac{1}{x}) और (g(x)=x-\frac{1}{x}) हैं, तो (\(f^2-g^2\)(x)) क्या होगा?

If (f(x)=x+\frac{1}{x}) and (g(x)=x-\frac{1}{x}), what is (\(f^2-g^2\)(x))?

Explanation opens after your attempt
Correct Answer

A. (4)

Step 1

Concept

(f-2-g-2=(f-g)(f+g)=\frac{2}{x}\cdot2x=4), where \(x\neq0\). Using an identity makes the calculation shorter.

Step 2

Why this answer is correct

The correct answer is A. (4). (f-2-g-2=(f-g)(f+g)=\frac{2}{x}\cdot2x=4), where \(x\neq0\). Using an identity makes the calculation shorter.

Step 3

Exam Tip

(f-2-g-2=(f-g)(f+g)=\frac{2}{x}\cdot2x=4), जहाँ \(x\neq0\)। पहचान का प्रयोग गणना को छोटा करता है।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=x+\frac{1}{x}) और (g(x)=x-\frac{1}{x}) हैं, तो (\(f^2-g^2\)(x)) क्या होगा? / If (f(x)=x+\frac{1}{x}) and (g(x)=x-\frac{1}{x}), what is (\(f^2-g^2\)(x))?

Correct Answer: A. (4). Explanation: (f-2-g-2=(f-g)(f+g)=\frac{2}{x}\cdot2x=4), जहाँ \(x\neq0\)। पहचान का प्रयोग गणना को छोटा करता है। / (f-2-g-2=(f-g)(f+g)=\frac{2}{x}\cdot2x=4), where \(x\neq0\). Using an identity makes the calculation shorter.

Which concept should I revise for this Mathematics MCQ?

(f-2-g-2=(f-g)(f+g)=\frac{2}{x}\cdot2x=4), where \(x\neq0\). Using an identity makes the calculation shorter.

What exam hint can help solve this Mathematics question?

(f-2-g-2=(f-g)(f+g)=\frac{2}{x}\cdot2x=4), जहाँ \(x\neq0\)। पहचान का प्रयोग गणना को छोटा करता है।