यदि (f(x)=x+2) और (g(x)=x-2-4) हैं तो (\left\(\frac{g}{f}\right\)(x)) का सरल रूप क्या है?

If (f(x)=x+2) and (g(x)=x-2-4) then what is the simplified form of (\left\(\frac{g}{f}\right\)(x))?

Explanation opens after your attempt
Correct Answer

A. (x-2), \(x\ne -2\)

Step 1

Concept

(\frac{g}{f}=\frac{x-2-4}{x+2}=\frac{(x-2)(x+2)}{x+2}=x-2), but \(x\ne -2\). Exclude the zero of the cancelled factor too.

Step 2

Why this answer is correct

The correct answer is A. (x-2), \(x\ne -2\). (\frac{g}{f}=\frac{x-2-4}{x+2}=\frac{(x-2)(x+2)}{x+2}=x-2), but \(x\ne -2\). Exclude the zero of the cancelled factor too.

Step 3

Exam Tip

(\frac{g}{f}=\frac{x-2-4}{x+2}=\frac{(x-2)(x+2)}{x+2}=x-2), पर \(x\ne -2\)। रद्द किए गए गुणनखंड का शून्य भी हटाएँ।

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यदि (f(x)=x+2) और (g(x)=x-2-4) हैं तो (\left\(\frac{g}{f}\right\)(x)) का सरल रूप क्या है? / If (f(x)=x+2) and (g(x)=x-2-4) then what is the simplified form of (\left\(\frac{g}{f}\right\)(x))?

Correct Answer: A. (x-2), \(x\ne -2\). Explanation: (\frac{g}{f}=\frac{x-2-4}{x+2}=\frac{(x-2)(x+2)}{x+2}=x-2), पर \(x\ne -2\)। रद्द किए गए गुणनखंड का शून्य भी हटाएँ। / (\frac{g}{f}=\frac{x-2-4}{x+2}=\frac{(x-2)(x+2)}{x+2}=x-2), but \(x\ne -2\). Exclude the zero of the cancelled factor too.

Which concept should I revise for this Mathematics MCQ?

(\frac{g}{f}=\frac{x-2-4}{x+2}=\frac{(x-2)(x+2)}{x+2}=x-2), but \(x\ne -2\). Exclude the zero of the cancelled factor too.

What exam hint can help solve this Mathematics question?

(\frac{g}{f}=\frac{x-2-4}{x+2}=\frac{(x-2)(x+2)}{x+2}=x-2), पर \(x\ne -2\)। रद्द किए गए गुणनखंड का शून्य भी हटाएँ।