यदि (f(x)=x-2-4x+4) और (g(x)=x-2) हैं, तो \(\frac{f}{g}\) का शून्य कहाँ होगा?

If (f(x)=x-2-4x+4) and (g(x)=x-2), where is \(\frac{f}{g}\) zero?

Explanation opens after your attempt
Correct Answer

A. कहीं नहींnowhere

Step 1

Concept

(\frac{f}{g}=\frac{(x-2)2}{x-2}=x-2), but (x=2) is not in the domain. Hence there is no zero.

Step 2

Why this answer is correct

The correct answer is A. कहीं नहीं / nowhere. (\frac{f}{g}=\frac{(x-2)2}{x-2}=x-2), but (x=2) is not in the domain. Hence there is no zero.

Step 3

Exam Tip

(\frac{f}{g}=\frac{(x-2)2}{x-2}=x-2), पर (x=2) डोमेन में नहीं है। इसलिए शून्य नहीं मिलता।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=x-2-4x+4) और (g(x)=x-2) हैं, तो \(\frac{f}{g}\) का शून्य कहाँ होगा? / If (f(x)=x-2-4x+4) and (g(x)=x-2), where is \(\frac{f}{g}\) zero?

Correct Answer: A. कहीं नहीं / nowhere. Explanation: (\frac{f}{g}=\frac{(x-2)2}{x-2}=x-2), पर (x=2) डोमेन में नहीं है। इसलिए शून्य नहीं मिलता। / (\frac{f}{g}=\frac{(x-2)2}{x-2}=x-2), but (x=2) is not in the domain. Hence there is no zero.

Which concept should I revise for this Mathematics MCQ?

(\frac{f}{g}=\frac{(x-2)2}{x-2}=x-2), but (x=2) is not in the domain. Hence there is no zero.

What exam hint can help solve this Mathematics question?

(\frac{f}{g}=\frac{(x-2)2}{x-2}=x-2), पर (x=2) डोमेन में नहीं है। इसलिए शून्य नहीं मिलता।