यदि (f(x)=x-2-2x) और (g(x)=x-2) हों, तो (\left\(\frac{f}{g}\right\)(x)) का सरल रूप क्या है?

If (f(x)=x-2-2x) and (g(x)=x-2), what is the simplified form of (\left\(\frac{f}{g}\right\)(x))?

Explanation opens after your attempt
Correct Answer

A. \(x,\ x\neq 2\)

Step 1

Concept

(\frac{x-2-2x}{x-2}=\frac{x(x-2)}{x-2}=x), but \(x\neq 2\). A cancelled factor does not remove the original restriction.

Step 2

Why this answer is correct

The correct answer is A. \(x,\ x\neq 2\). (\frac{x-2-2x}{x-2}=\frac{x(x-2)}{x-2}=x), but \(x\neq 2\). A cancelled factor does not remove the original restriction.

Step 3

Exam Tip

(\frac{x-2-2x}{x-2}=\frac{x(x-2)}{x-2}=x), पर \(x\neq 2\)। cancelled factor से मूल restriction खत्म नहीं होती।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=x-2-2x) और (g(x)=x-2) हों, तो (\left\(\frac{f}{g}\right\)(x)) का सरल रूप क्या है? / If (f(x)=x-2-2x) and (g(x)=x-2), what is the simplified form of (\left\(\frac{f}{g}\right\)(x))?

Correct Answer: A. \(x,\ x\neq 2\). Explanation: (\frac{x-2-2x}{x-2}=\frac{x(x-2)}{x-2}=x), पर \(x\neq 2\)। cancelled factor से मूल restriction खत्म नहीं होती। / (\frac{x-2-2x}{x-2}=\frac{x(x-2)}{x-2}=x), but \(x\neq 2\). A cancelled factor does not remove the original restriction.

Which concept should I revise for this Mathematics MCQ?

(\frac{x-2-2x}{x-2}=\frac{x(x-2)}{x-2}=x), but \(x\neq 2\). A cancelled factor does not remove the original restriction.

What exam hint can help solve this Mathematics question?

(\frac{x-2-2x}{x-2}=\frac{x(x-2)}{x-2}=x), पर \(x\neq 2\)। cancelled factor से मूल restriction खत्म नहीं होती।